Can someone please help me with the steps in doing these questions below please?
In Canadian federal elections, 3 out of 4 voters usually cast their votes. In a riding with 60,000 voters,
a) how many people are expected to vote?
b) how many people are not expected to vote?
c) what is the expected ratio of voters who cast their votes to voters who do not cast their votes to total number of voters?
Equivalent ratios and proportions?
1.using proportion:
3:4=x:60,000
multiply the means and the extremes:
4x=180,000
divide both sides by 4:
4x/4=180,000/4
that will yield to:
x=45,000 or out of 60,000 canadian voters 45,000 will cast their votes.
2. just do no. 1 but now the ratio will be 3:1=45,000:x
multiply the means and the extremes:
3x=45,000
divide both sides with 3:
3x/3=45,000/3
that will yield to:
x=15,000 or out of the 60,000 canadian voters,15,000 canadians will NOT casts their votes.
3.3:1:4 or 45,000:15,000:60,000
checking:
45,000+15,000=60,000
60,000=60,000
Reply:a) 3/4 * 60,000 = 45000
b) Total voters - Voters = 60000 - 45000 = 15000
c) 3/4 : 1/4 : 1
= 3/4 : 1/4 : 4/4
(cancelling away the denominators)
= 3 : 1 : 4
Reply:a) 45,000 (3/4 of 60,000 is 45,000)
b) 15,000 (1/4 of 60,000 is 15,000)
c) 3:1:4 or 45,000: 15,000: 60,000 (whose votes were casted: not casted: total number of voters)
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