What is the difference between the line mention below:-?

(It is in the c program.In linked list.)


struct node


{


int data;


struct node *link;


};


/*when we allocate the memorary for the new node */


void append(struct node **q,int data)


{


struct *temp;


temp = malloc(sizeof(struct node); /* 1 */


/* AND */





temp = (struct node *) malloc( sizeof (struct node) ); /* 2 */





}





/* tell the difference between different code for allocation


in line 1 we dont mention the cast type


%26amp;


in line second we mention the cast type.


*/

What is the difference between the line mention below:-?
For all intents and purposes there is no difference between the two. Since malloc returns a void *, casting (example 2) is purely optional. The only real difference only comes into play if you forget to include stdlib (example 1 will generate an error because the compiler defaults to functions returning int's if a formal declaration is not found, example 2 might slip through the cracks since you're doing an explicit cast).
Reply:Both works fine. But, the second is considered as 'Good programming practice'.
Reply:Hi :





plz may you explain more , or put another question





thanx


have a nice day